Project Euler #29: Distinct Powers

Consider all integer combinations of a^^b for 2 ≤ a ≤ 5 and 2 ≤ b ≤ 5:

2²=4, 2³=8, 2⁴=16, 2⁵=32
3²=9, 3³=27, 3⁴=81, 3⁵=243
4²=16, 4³=64, 4⁴=256, 4⁵=1024
5²=25, 5³=125, 5⁴=625, 5⁵=3125

If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:

4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125

How many distinct terms are in the sequence generated by a^b for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100?

Taking advantage of Python’s arbitrary integer length, here is my solution

dup = set()
distinct = set()

for a in range(2, 101):
     for b in range(2, 101):
          foo = pow(a, b)
          if foo not in dup:
               distinct.add(foo)
               dup.add(foo)

print len(distinct)