A number chain is created by continuously adding the square of the digits in a number to form a new number until it has been seen before.
For example,
44 → 32 → 13 → 10 → 1 → 1
85 → 89 → 145 → 42 → 20 → 4 → 16 → 37 → 58 → 89
Therefore any chain that arrives at 1 or 89 will become stuck in an endless loop. What is most amazing is that EVERY starting number will eventually arrive at 1 or 89.
How many starting numbers below ten million will arrive at 89?
#include <iostream> bool squareDigitCheck(int passedInt); int main(void) { int total = 0; for(int i = 1; i < 10000000; i++) { if(squareDigitCheck(i)) { total++; } } std::cout << "There are " << total << " square digits that summate to 89 under 10000000"; return 0; } bool squareDigitCheck(int passedInt) { int squareBuff = 0, digitBuff; while(passedInt != 89) { while(passedInt) { digitBuff = passedInt % 10; passedInt /= 10; squareBuff += (digitBuff * digitBuff); } passedInt = squareBuff; squareBuff = 0; if(passedInt == 1) { return false; } } return true; }