Project Euler #8: Largest Product in a Series

The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832.

73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450

Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?

The answer is 23514624000, as surmised by the following program.

#include <iostream>
#include <vector> 
#include <fstream>

int main(void)
{
	std::string filePath = "./numbers.txt";
	std::ifstream inFile;
	unsigned long long largestProd = 0;
	unsigned long long prodBuff;
	std::vector<int> intVect;
	char szBuff;

	inFile.open(filePath.c_str());
	
	// Load numbers into program
	while(inFile.get(szBuff))
	{
		// Convert from ASCII value to integer literal
		intVect.push_back(szBuff-48);
	}
	
	// Iterate through the vector, stopping 13 before intVect.end()
	for(int i = 0; i < (intVect.size()-13); i++)
	{
		// Set prodBuff to the first of the 13 digits
		prodBuff = intVect[i];
	
		// Iterate through the list, multiplying against itself
		for(int j = 1; j < 13; j++) { prodBuff *= intVect[i+j]; } // If is larger than current largest, replace if(prodBuff > largestProd)
		{
			largestProd = prodBuff;
		}
	}
	// Output the answer
	std::cout << largestProd;
}

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