Project Euler #6: Sum square difference

The sum of the squares of the first ten natural numbers is,

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

#include <iostream>

int main(void)
{
      double sumOfSquare = 0;
      double squareOfSum = 0;
      for(int i = 0; i <= 100; i++)
      {
            squareOfSum += i;
            sumOfSquare += (i*i);
      }
      squareOfSum *= squareOfSum;
      std::cout << std::endl << std::fixed << "Square of the sum: " << squareOfSum;
      std::cout << std::endl << std::fixed << "Sum of the squares: " << sumOfSquare;
      std::cout << std::endl << std::fixed << "Their difference is: " << squareOfSum - sumOfSquare;
return 0;
}