A Pythagorean triplet is a set of three natural numbers, a < b < c, for which, a2 + b2 = c2 For example, 32 + 42 = 9 + 16 = 25 = 52. There exists exactly one Pythagorean triplet for which a + b + c = 1000. …
The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832. 73167176531330624919225119674426574742355349194934 96983520312774506326239578318016984801869478851843 85861560789112949495459501737958331952853208805511 12540698747158523863050715693290963295227443043557 66896648950445244523161731856403098711121722383113 62229893423380308135336276614282806444486645238749 30358907296290491560440772390713810515859307960866 70172427121883998797908792274921901699720888093776 65727333001053367881220235421809751254540594752243 52584907711670556013604839586446706324415722155397 53697817977846174064955149290862569321978468622482 83972241375657056057490261407972968652414535100474 82166370484403199890008895243450658541227588666881 16427171479924442928230863465674813919123162824586 17866458359124566529476545682848912883142607690042 24219022671055626321111109370544217506941658960408 07198403850962455444362981230987879927244284909188 84580156166097919133875499200524063689912560717606 05886116467109405077541002256983155200055935729725 71636269561882670428252483600823257530420752963450 Find the thirteen adjacent digits in the …
A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99. Find the largest palindrome made from the product of two 3-digit numbers. The answer is 906609, as surmised from the following program. #include <iostream> …
The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143 ? The answer is 6857, as surmised by the following program. #include <iostream> #include <math.h> int main(void) { unsigned long long factoredNumber = 600851475143; unsigned long long seed …
The sum of the primes below 10 is 2 + 3 + 5 + 7 = 17. Find the sum of all the primes below two million. The answer is 142913828922, as surmised by the following program in C++. #include <iostream> #include <vector> #include <fstream> #define SIEVEMAX 2000000 int …
By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13. What is the 10 001st prime number? I utilized a Sieve of Erastothenes with a bit vector implemented in C++ to solve this problem. The answer …
Your assignment will be to write a Y86-64 program to perform bubblesort. For reference, the following C function implements bubblesort using array referencing: /* Bubble sort: Array version */ void bubble_a(long *data, long count) { long i, last; for(last = count-1; last > 0; last–){ for( i = 0; i …
/* Sources: http://www.gnu.org/software/libc/manual/html_node/Getopt.html https://en.wikipedia.org/wiki/C_dynamic_memory_allocation Computer Systems A Programmers Perspective */ #include <stdlib.h> #include <stdio.h> #include <getopt.h> #include “cachelab.h” #include <math.h> #include <strings.h> typedef unsigned long long int address; typedef int bool; #define true 1 #define false 0 typedef struct // Structure for holding command line parameters given when calling …
Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, … By considering the terms in the Fibonacci sequence whose values do not …
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. Solution in Python total = 0; …