Using names.txt (right click and ‘Save Link/Target As…’), a 46K text file containing over five-thousand first names, begin by sorting it into alphabetical order. Then working out the alphabetical value for each name, multiply this value by its alphabetical position in the list to obtain a name score.
For example, when the list is sorted into alphabetical order, COLIN, which is worth 3 + 15 + 12 + 9 + 14 = 53, is the 938th name in the list. So, COLIN would obtain a score of 938 × 53 = 49714.
What is the total of all the name scores in the file?
The solution is 871198282, as surmised from the following program.
#include <iostream>
#include <vector>
#include <algorithm>
#include <fstream>
int main(void)
{
std::string filePath = "./p022_names.txt";
// For stripping quotations and reading from inFile
std::string stringBuff;
// For holding first names; vector for sort algorithm
std::vector<string> firstNames;
// Holds the total names
unsigned long nameScore = 0;
int scoreBuff;
std::ifstream inFile;
inFile.open(filePath.c_str());
while(!inFile.eof())
{
// Read from infile delimited by commas
std::getline(inFile, stringBuff, ',');
// Erase leading quotation
stringBuff.erase(0, 1);
// Erase trailing quotation
stringBuff.erase(stringBuff.size() - 1);
// Push onto the string vector
firstNames.push_back(stringBuff);
}
// Sort the names
std::sort (firstNames.begin(), firstNames.end());
// Increment through the vector of sorted strings
for(auto vectorIt = firstNames.begin(); vectorIt != firstNames.end(); vectorIt++)
{
// Clean up
scoreBuff = 0;
// Increment through each character of the string
for(auto stringIt = (*(vectorIt)).begin(); stringIt != (*(vectorIt)).end(); stringIt++)
{
// static_cast to ascii value, subtract 64 to reduce to alphabetical indexing
scoreBuff += ((static_cast<int>(*(stringIt)))-64);
}
// Multiply by distance from current iterator position to beginning element
scoreBuff *= (std::distance(firstNames.begin(), vectorIt) + 1);
nameScore += scoreBuff;
}
std::cout << std::endl << nameScore << " is the final namescore";
return 0;
}